Get Speed in Maths of Competitive Exam By Short Tricks... - BRIJ....MAAHI....KHANT
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22/02/2016

Get Speed in Maths of Competitive Exam By Short Tricks...

Get Speed in Maths of Competitive Exam By Short Tricks...

Trick-1..
Trick of number 9
Take the nine digits in order and remove the 8: 12345679.
Then multiply by 9:
12345679*9 = 111111111
now tries multiplication by the multiples of 9:
12345679*18 = 222222222
12345679*27 = 333333333
12345679*36 = 444444444
12345679*45 = 555555555
12345679*54 = 666666666
12345679*63 = 777777777
12345679*72 = 888888888 
12345679*81 = 999999999
Trick-2..
Trick for Calculate Reminder On Dividing The Number By 27 And 37
Consider number 34568276, we have to calculate the reminder on dividing this number by 27 and 37 respectively.
make triplets as written below starting from units place
34.........568..........276
now sum of all triplets = 34+568+276 = 878
divide it by 27 we get reminder as 14
divide it by 37 we get reminder as 27 

For Example,

other examples for the clarification of the rule
let the number is 2387850765
triplets are 2...387...850...765
sum of the triplets = 2+387+850+765 = 2004
on revising the steps we get 
2......004 
sum = 6
divide it by 27 we get reminder as 6
divide it by 37 we get reminder as 6
Trick-3..
Trick for Calculate Reminder On Dividing The Number By 3
Method: - first calculate the digit sum, then divide it by 3, the reminder in this case will be the required reminder
For example: - 1342568
let the number is as written above 
its digit sum = 29 = 11 = 2
so reminder will be 2 

For Example,
34259677858
digit sum of the number is 64 = 10 = 1
reminder is 1
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